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Mathematics 14 Online
OpenStudy (anonymous):

I'll ask in comment

OpenStudy (anonymous):

Find x such that \[2014^{\log_{10}(x) }=11^{\log_{10}(1+3+5+...+4027)} \]

ganeshie8 (ganeshie8):

start by taking log both sides

ganeshie8 (ganeshie8):

and simplify the sum in exponent : 1+3+5+... +4027 = 2014^2

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