Question

I'll ask in comments

Answer 1

The equations below are written in a code such that each digit represents some other digits. Find the exact value of 2014 , given that each of the following is true in ordinary arithmetic.
\[8+3=3\]\[9+7=6\]\[77*5=00\]\[5+4=1\]\[6+0=99\]\[3-2=9\]

Answer 2

Hey man, don't get mad but im commenting to get the credits.

Answer 3

8 + 3 = 3

This seems to be telling us that 8 represents the real 0.
I think..
Hmm what else..

Answer 4

6 + 0 = a two digit number, hmmmm

Answer 5

6+0=99
Oh oh oh, and the two digit number is 99.
They're the same digit!

Since two single digit numbers can't add up to 20 or higher it means that they add up to 11.
So 9 represents the real 1 digit.

Answer 6

77*5=00

Hmmmm...
The only way for this to work out (with the numbers we have left) is by doing:
22*3=66
33*2=66
22*4=88
44*2=88

So 7 and 5 have to be 2 3 or 4. hmmmmmm

Answer 7

@wio
help me figure this out XD
fun puzzle!

Answer 8

Hmmmm

Answer 9

you have to solve with farts.

Answer 10

oh my :o

Answer 11

Are the operations also switched?

Answer 12

No, operations are true I think.

Answer 13

I think I've got these two values correct.
8 --> `0`
9 --> `1`

And I think these are the only options for these numbers... hmm
0 --> `6`, `8`
5 --> `2`, `3`, `4`
7 --> `2`, `3`, `4`

Answer 14

so far 8=0, 9=1

Answer 15

0 = 5?

Answer 16

77*5=00

Since 1 and 0 are already taken, it means 7 and 5 have to be 2 or larger.
We can't get 55 (which is what our 00 would be hiding as) without 7 or 5 being a 1, right? :o

Answer 17

7=5?

Answer 18

77*5=00

`55` *5=00

The fake 5 would have to be 2 or larger,
this multiplication wouldn't result in a 2 digit answer :(
ya i dont think that works. hmm

Answer 19

Well, 5 and 7 are 2, 3, or 4. They both can't be the same digit though. this means they both can't be 3. This means 0 is even.

Answer 20

We know 5*7=0

Answer 21

oo i came up with some numbers :O
kinda took a shot in the dark.. lemme see if it worked out.. gotta check the equations again.

Answer 22

3-3=8 so 8=0

Answer 23

0=5

Answer 24

8+3=3
3−2=9

These are the only equations for 3 and 2, which means at some point we will have to guess and check.

Answer 25

6=9

Answer 26

based on what i posted earlier, i narrowed fake 0 down to 6 or 8.
I had to do a little guess work.

I let it equal 8, and everything unraveled nicely :O
i think ive got these values correct.

Should i paste them? Or would that ruin the fun?

Answer 27

huh lol
giv som hints :P

Answer 28

Well, we should try to do it without any guesses first.

Answer 29

We know 0 is even.

Answer 30

9 is the real 1.
You can use that to establish a bunch of nice relationships (numbers that are 1 apart).

Answer 31

6+0=99
6 + even = odd
this means that 6 is odd.

9+7=6
odd + 7 = odd

This means 7 is even. So 7 is 2 or 4

Answer 32

which also means that 5 is 2 or 4, since 00 is even.

Answer 33

the pieces are falling into place! :D git it wio!!

Answer 34

wait, nevermind that isn't true.

Answer 35

no? :O

Answer 36

if 77 is even, then 5 can still be odd and we'd get 00 = 66

Answer 37

oh true :3

Answer 38

7=3

Answer 39

so we have 7 = 2,4 and 5 = 2,3,4 but we don't have any way to actually solve without guessing at this point, I think.

Answer 40

lets see though...

Answer 41

8=0,0=5,9=1,6=9,7=3 are these ok?

Answer 42

I honestly don't give a rat's buttocks whether your answer is ok if you cant actually justify it.

Answer 43

6 + 0 = 99 --> `9` + `5` = `11`
Hmm your numbers don't seem to hold true :(

Answer 44

Lets see...

6+0=99

Since 11 - 8 = 3 and 11 - 6 = 5, that means that 6 is 3 or 5

9+7=6

Since 3-1 = 2 and 5-1 = 4, this means 7 is 2 or 4

Answer 45

That pretty much uses all the info given. I wonder if there are multiple solutions.

Answer 46

mm i hope not.. that would make my guessing approach seem kinda silly. XD

Answer 47

This is what I have reduced it to so far.

0 - 6,8
1 - 5,6,7,8,9
2 - 2,3,4,5,6,7,8
3 - 3,4,5,6,7,8,9
4 - 3,4,5,6,7
5 - 2,3,5
6 - 3,5
7 - 2,4
8 - 0
9 - 1

Answer 48

I agree that 0 - 6,8

I guessed from that point.
I let 0=8 and got a solution set.
0=6 ended up with a conflict.

Not the most elegant way to solve it I guess...
But it worked I think. D:

Answer 49

i wrote 0 = 5 it should be 0 = 2
9 + 2 = 11

Answer 50

0 can't be 2.

77*5 = 00

The only way that's true is if 77*5 --> 11*2 or 22*1.
But we've already used our 1.

Answer 51

okay, so we know that 2 and 3 are sequential. That does allow us to make some eliminations.

Answer 52

If 7 is 2 then 6 ix 3, and 5 is 4.
If 7 is 4 then 6 is 5, and 5 is 2 or 3.

In either case, 2, 3, and 4 are taken. So 2 can't be among them.

0 - 6,8
1 - 5,6,7,8,9
2 - 5,6,7,8
3 - 6,7,8,9
4 - 3,4,5,6,7
5 - 2,3,5
6 - 3,5
7 - 2,4
8 - 0
9 - 1

Answer 53

hmm, not sure why I think 5 is 2,3,5.... where did that come from exactly...

Answer 54

oh, because of multiplication with 77, no wonder...

Answer 55

We know 4 shouldn't be 2,3 or 4 as well.
This means 1 can't be lower than 4 and 5's lowest values.

0 - 6,8
1 - 7,8,9
2 - 5,6,7,8
3 - 6,7,8,9
4 - 5,6,7
5 - 2,3,5
6 - 3,5
7 - 2,4
8 - 0
9 - 1

Answer 56

whoops,

0 - 6,8
1 - 7,8,9
2 - 5,6,7,8
3 - 6,7,8,9
4 - 5,6,7
5 - 2,3,4
6 - 3,5
7 - 2,4
8 - 0
9 - 1

Answer 57

It looks like at this point you do have to guess and check.

Answer 58

However, any guess will force a lot of other numbers to be in place.

If we pick 7 is 2, then
6 is 3
5 is 4
4 is 5
0 is 8
1 is 9
2 is 6
3 is 7

Answer 59

i oly think of it as leaner system

Answer 60

ill use QSB to solve it lol

Answer 61

If we pick 7 is 4 then
0 - 8
1 - 7,8
2 - 6
3 - 7
4 - 5
5 - 2,3
6 - 5
7 - 4
8 - 0
9 - 1

this leads to a problem because we can't get any digit to be 9.

So then by elimination we know 7 is 2.

Answer 62

0 - 8
1 - 9
2 - 6
3 - 7
4 - 5
5 - 4
6 - 3
7 - 2
8 - 0
9 - 1

Answer 63

22*4 =88
7 =2, 5 = 4 , 8=0

Answer 64

So then\[
8+3=3\\
9+7=6\\
77∗5=00\\
5+4=1\\
6+0=99\\
3−2=9
\]becomes\[
0+7=7\\
1+2=3\\
22∗4=88\\
4+5=9\\
3+8=11\\
7−6=1
\]

Answer 65

The contingency tree is so deep that you have to guess and check.

Answer 66

i used QSB to solve it it says its unbounded lol
so leanerly cant be solved without guessing :o