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Differential Equations
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2/3b+10+1/3b How do i solve that? I can't solve it. Please Help Me
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ok but how do I solve it I haven't done problem like this.
It is 2/3b+1/3b +10 so add the one with same bottom first which makes it (2+1)/3b +10 = 3/3b +10. Now cancel both 3's, we get 1/b +10
So that makes it by making a common denominator (1+10b)/b
How do you get that I don't understand how don't you divde
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