Question

Find the magnitude ||v|| and direction angle θ, to the nearest tenth of a degree, for the given vector v. v = -4i - 3j

Answer 1

if w= a i + b j
\[
|| w|| = \sqrt{ a^2 + b^2}
\]
What is the norm of u=-4i - 3j ?

Answer 2

\[
||u|| = \sqrt{ (-4)^2 + (-3)^2}=\sqrt{ 25}=5
\]

Answer 3

So would this
216.9°
be the other part?

Answer 4

Yes

Answer 5

Thank you!

Answer 6

YW