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Algebra
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Please show me the work-an equation of the line that is perpendicular to the given line -10x + 8y = 3 and passes through the given point (15, 12).
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8y=10x+3
y=10/8x+3/8
now take the slope and plug it into the equation \[y-y_o=m(x-x_o)\]
\[y-12=\frac{10}{8}(x-15)\]
is that the answer?
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you could probably simplify it a bit more if you wanted to
how would I goabout that?
How do I graph it
y=1.25x-6.75
I would then pick a number for x try zero and one. at point (0,-6.75) and at (1,-5.5) you can then plot those two points on a graph and connect the dots
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