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(sin^-1(x))/sqrt (1-x^(2))
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is there an equal sign somewhere?
\[\int\limits \frac{ \arcsin x }{ \sqrt{1-x^2} }dx=\\ ?\]
if yes use substitution u = arcsin x
\[\int\limits \frac{ \arcsin x }{ \sqrt{1-x^2} }dx=\\ u=\arcsin x \\du =\frac{ 1 }{ \sqrt{1-x^2}}dx\\\]
its turn to \[\int\limits u du = \frac{ u^2 }{2 }+c = \frac{ (arcsinx)^2 }{2 }+c\]
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