Ask your own question, for FREE!
Chemistry 22 Online
OpenStudy (anonymous):

a 0.04356 g sample of gas occupies 10.0 mL at 291.5K and 1.10 atm upon further analysis the compound is found to be 25.305 percent C and 74.695 percent Cl what is the molecular formula

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!