Question

logx-log(x+4)=-1
log(x/(x+4))=-1
?

Answer 1

So far, so good

Now convert that logarithmic equation to exponential form

You do this by using the rule

log(x) = y ----> x = 10^y

---------------------------------------------------------

So that means

log(x/(x+4))=-1

turns into

x/(x+4) = 10^(-1)

x/(x+4) = 1/(10^1)

x/(x+4) = 1/10

and I'll let you finish up

Answer 2

x=x+4/10
? That's actually where I was, I should have gone further, because it's that point where I don't know how to get the variable on one side

Answer 3

From here, you cross multiply

x/(x+4) = 1/10

10x = 1(x+4)

10x = x + 4

10x - x = 4

9x = 4

x = 4/9

Answer 4

Don't forget to check all possible answers. So plug x = 4/9 back into the original equation and simplify. You should get an identity.

Answer 5

ahhhhh.