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Find an equation of the line. Horizontal; through (-3,-11) Write the equation in standard form.
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This is vectors right?
what is vectors ?
...calculus, okay i can still do this using simper math are you familiar with this equation = y-y1 =m(x-x1)
yes i am
Okay, you have y1, and x1 already from the point given (-3,-11) and m is slope, what is the slope of a horizontal line?
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the slope is 0 ?
yup so y-(-11)=0 (because anything multiplied by zero is zero and then basically you have y + 11=0 so y=-11
in standard form though its just y+11=0
oh thank you
no problem
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