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if f(x) =x^2-x^2-5, find f(-2/3)
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is it really x^2 - x^2 - 5 ? or is there a typo?
x^3-x^2-5
ok thanks
f(x) = x^3-x^2-5 f(-2/3) = (-2/3)^3-(-2/3)^2-5 ... replace ALL copies of x with -2/3 f(-2/3) = -8/27-4/9-5 I'll let you finish up
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-155/7
good
oh sorry, it should be -155/27
missed the 2
I have seen where I made the mistake....i did -8/27-(-4/9)-7
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i see
oh yea..sorry for that
no worries
you still have time, I got few more questions.
I can do one more
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