Estimate the limit by substituting smaller and smaller values of h.

lim (6+h)^3 - 216
h-0 --------------
h

how do you do this? are you using h=0.1, h=0.01 and h=0.001 ?

:/ thank you!!

Question

Estimate the limit by substituting smaller and smaller values of  h.

lim    (6+h)^3  -  216
h->0 --------------
                    h

how do you do this? are you using h=0.1, h=0.01 and h=0.001 ?

:/ thank you!!

mertsj · Answer

yes.  those values would be fine.  Substitute them and see what number the answer approaches.  That is the limit.

anonymous · Answer

h=0.1..... 109.81

h=0.01.... 1081.801

h=0.001......108.018001

do those look right? if so, what happens from here?

mertsj · Answer

Looks to me like the answers are getting closer and closer to 108.  So I would say that the limit is 108

anonymous · Answer

ohh okay i see:) awesome! thanks!!!

mertsj · Answer

yw