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Mathematics 20 Online
OpenStudy (anonymous):

Use the quadratic formula to solve: 2y^2+6y-8=0

OpenStudy (anonymous):

Do you know what your a b and c terms are?

OpenStudy (anonymous):

Ax^2+Bx+C?

OpenStudy (anonymous):

it doesn't have to be x the variable can be y too

OpenStudy (anonymous):

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] is the quadratic formula so can you plub the values in?

OpenStudy (anonymous):

*plug

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