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OpenStudy (anonymous):

Please help me! Using a directrix of y = 2 and a focus of (3, -4), what quadratic function is created? f(x) = one twelfth (x - 3)2 - 1 f(x) = -one sixth (x + 3)2 + 1 f(x) = one sixth (x - 3)2 + 1 f(x) = -one twelfth (x - 3)2 - 1

OpenStudy (anonymous):

anyone?

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