Question

I would actually like to learn how to do this problem... please help me?

Using a directrix of y = 2 and a focus of (3, -4), what quadratic function is created?

f(x) = one twelfth (x - 3)2 - 1

f(x) = -one sixth (x + 3)2 + 1

f(x) = one sixth (x - 3)2 + 1

f(x) = -one twelfth (x - 3)2 - 1