will give medal.can someone help me?
With what?
with a problem in algebra
What is your question?
\[2^{2}+3x+2\] separate the two values with commas
i have to rewrite the problem
\[2^{2}+3x=2\]
Subtract 2^2 from 2. You would then get 3x = 2-(2^2), which is 3x = -2. You would then be able to divide -2 by 3, which would then end up with an answer of x = -2/3. However, I think you wrote the problem wrong.. If you're supposed to end up with two values, the problem should be 2x^2 + 3x + 2
i did write it wrong
In that case, you would use the quadratic formula.
If you have the equation, you would use 2 as a, 3 as b, and -2 as c.
Then you can plug it in and get two answers.
so whts the answer.im still confused
|dw:1392051900370:dw| Do you get that part so far?
yes
Now all you do is just plug 2 in for a, 3 in for b, and 2 in for c.. |dw:1392052672749:dw|
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