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What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and ground is 0.80? Please explain...
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Max velocity of car is given by; V=urg(u=coeff. of friction) Here the road is straight so,we can ignore the radius V=ug =(0.80).(9.8) =7.84m/s^2 so a = 7.84 m/s^2
So it is a s simple as multiplying the coefficient of friction by gravity?
yes
Thank you!! I jumped into a 2nd level college Physics class after not having Physics for around 11 years. Feeling desperate and for the most part lost.
your welcome
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