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OpenStudy (anonymous):

A ship sails due south for 200 km, then due east for 50 km. What are the distance AND bearing of the starting point from the ship. Can someone check this for me I have √(200^2 +50^2) = 206.155km and tanθ = 50/200 = 1/4 → tan(14°) = 1/4 →14°

OpenStudy (noorik.):

your solution is correct

OpenStudy (anonymous):

thank you!

OpenStudy (noorik.):

you're welcome

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