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OpenStudy (anonymous):
what is the derivative of 4cos2pi(s) and 3sin2pi(s)?
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OpenStudy (anonymous):
the derivative of cosine is minus sine so the first one, by the chain rule, is \[-8\pi\sin(2\pi s)\]
OpenStudy (anonymous):
second one is similar, but the derivative of sine is cosine, so again by the chain rule you get \[6\pi\cos(2\pi x)\]
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