Question

alg

Answer 1

Hey @jigglypuff314 !

Answer 2

factor by grouping
y = 3x^3 - x^2 - 27x + 9
= x^2(3x-1) - 9(3x-1)
= (3x-1)(x^2 -9) and you can factor the x^2-9 = (x+3)(x-3)

Answer 3

correct :)

Answer 4

when it is an exponent to and exponent
the exponents multiply
so m^8^(1/4) = m^(8*1/4) = m^2

Answer 5

is it
16 16/(16^2)
------- or --------- ?
16^2/4 4

Answer 6

then yeah, you were correct :)

Answer 7

it's a difference of squares
y = a^2 - 2ab + b^2 = (a - b)^2

Answer 8

replace a = x
and b = 6

Answer 9

yep :)

Answer 10

idk this stuff, but look to me like there should be a y intercept at y = 2
http://www.wolframalpha.com/input/?i=2+*+4%5Ex

Answer 11

and I've gtg :/