Question

@Ryan88 Help please sorry lol

Answer 1

@ganeshie8

Answer 2

\[c^2 = a^2 +b^2\] a = 6; b = ?; c = 12

\[12^2= 6^2 +b^2\]square the 12 and 6\[144 = 36 +b^2\]Subtract 36 from both sides\[108= b^2\] take the square root of both sides\[\sqrt{108}= b\]

Answer 3

im not doing those no more this is diffrent did u read the question @Ryan88

Answer 4

the answer choices are 2, 12 radical 3, 1/2, 6 radical 3

Answer 5

Well \[\sqrt{108}= 6\sqrt{3}\]