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OpenStudy (anonymous):
Solve for x: 1/3x - 3 = 2x + 4
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OpenStudy (texaschic101):
1/3x - 3 = 2x + 4 --- multiply the entire equation by 3 x - 9 = 6x + 12 -- subtract 6x from both sides x - 6x - 9 = 12 -- add 9 to both sides x - 6x = 12 + 9 -- combine like terms -5x = 21 x = -21/5
OpenStudy (anonymous):
can you work it out please
OpenStudy (nirmalnema):
is x in numenator of denominator..in 1/3x
OpenStudy (texaschic101):
I thought it was (1/3) x.....if it is not, then my answer is wrong
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