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the equation of line AB is y=5x+1. write an equation of a line parallel to line AB in slope-intercept form that contains point (4,5).
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ok...look at your equation y = 5x + 1. Can you tell me what the slope is ?
I am in a good mood....slope is 5. Parallel line will have same slope. Now use y = mx + b slope(m) = 5 (4,5) x = 4 and y = 5 now we sub and solve for b 5 = 5(4) + b 5 = 20 + b 5 - 20 = b -15 = b so your parallel line will be : y = 5x - 15
understand ?
yes thankyou (:
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