Question

Perform the operation and leave the result in trigonometric form.

Answer 1

\[[(2/3)(\cos(\pi/3)+isin(\pi/3)][9(\cos(\pi/6)+isin(\pi/6)]\]

Answer 2

\(\large{ \bf {\color{red}{ r}}[cos(\theta)+isin(\theta)]\cdot {\color{blue}{ r}}[cos(\beta)+isin(\beta)]\\ \quad \\
\implies {\color{red}{ r}}\cdot {\color{blue}{ r}}[cos(\theta+\beta)+isin(\theta+\beta)]}\)

Answer 3

Notice that
\[
\frac \pi 6 + \frac \pi 3=\frac \pi 6 + \frac {2\pi} 6=\frac \pi 2
\]

Answer 4

So, the answer is pi/2?

Answer 5

I dont understand this, can someone show me how to solve this?