Question

help probability ?

Answer 1

?

Answer 2

I have a and C but I can't get B and I only have one attempt left so I need help!!!

Answer 3

i guess the first 3 should add up, what do u think?

Answer 4

well my answers so far were.... 1.08 ,0.40,
but they have been wrong!!! I tried doing 129-(?+?+?) but im getting it wron g

Answer 5

i divide it by 200 and nothing

Answer 6

Using the inclusion-exclusion principle:
$$
\large{
P(sf \cup bf \cup mf)\\
=P(sf)+P(bf)+P(mf)-P(sf\cap bf)-P(sf\cap mf)-\\
P(mf\cap bf)+P(sf \cap bf \cap mf)\\
=\cfrac{129}{200}+\cfrac{88}{200}+\cfrac{71}{200}-\cfrac{45}{200}-\cfrac{38}{200}-\cfrac{37}{200}+\cfrac{24}{200}\\
=\cfrac{129+88+71-45-38-37+24}{200}\\
=\cfrac{24}{25}\\
=0.96
}
$$
http://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle