Question

(x^2-25)/x

Answer 1

\[(a^2-b^2)=(a-b)(a+b)\]so\[\frac{x^2-25}{x}=\frac{x^2-5^2}{x}=\frac{(x-5)(x+5)}{x}\] not much else you can do with it, are you sure it wasnt\[\frac{x^2-25}{x+5}\]