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Is the reciprocal of 2/sin b = 2cscb?
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Well it is true that\[ \frac{1}{\sin (x)} = \csc(x) \]
yes
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ok. well I guess I didn't realize how it broke down into a reciprocal, like the actual breakdown of it>?
Start with\[ \frac{1}{\sin (x)} = \csc(x) \]Multiply both sides by \(2\) \[ \frac{2}{\sin (x)} = 2\csc(x) \]Let \(x=b\) \[ \frac{2}{\sin (b)} = 2\csc(b) \]
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ahhhh!!!thank you. greatly appreciated.
Pardon me, but the reciprocal of \(\dfrac{2}{\sin(b)} = \dfrac{\sin(b)}{2}\). :)
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