Find the equation of the hyperbola having center at the origin. Conjugate axis on the y-axis, eccentricity is square root of 41all over 5, equation of one directrix x= 25 square root of 41 all over 41.

Question

anonymous · Answer

@RadEn can you pls help me?

anonymous · Answer

@SolomonZelman can i have your help?

solomonzelman · Answer

$$\huge\color{blue}{  \frac{(x-h)^2}{a} - \frac{(y-k)^2}{b}  } $$

eccentricity =  (distance from center to focus along transverse axis)
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                                                 a   (or   semi-transverse axis)

solomonzelman · Answer

No, Idk, I forgot all this staff, sorry

anonymous · Answer

yeah, it's okay if that's the case. thanks anyway :)

anonymous · Answer

pls help @mathstudent55