Question

simplify completely:

Answer 1

\[=\frac{ 12x ^{3} }{ -2x }-\frac{ 4x ^{2} }{ -2x }+\frac{ 8x }{ -2x }=-6x ^{2}+2x-4\]
you can also solve it like this.
\[\frac{ 12x ^{3}-4x ^{2}+8x }{ -2x }=\frac{ -2x \left( -6x ^{2}+2x-4 \right) }{ -2x }=?\]

Answer 2

thanks :)

Answer 3

yw