The equation of the quadratic function with roots 6 and 10 and a vertex at (8, 2) is f of x equals 1/2x^2 plus 8x-30. True or false? Medals given(:
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Um..
well lots of ways to look at it... you know the roots so f(x) = a(x -6)(x -10) which is \[f(x) = a(x^2 - 16x + 60)\] looking at the given value of a, its a = 1/2 so substiute the vertex x = 8 and y = 2 so see if a = 1/2 so 2 = 1/2(8^2 -16(8) + 60) 2 = 1/2(-4) so does 2 = -2 thats what you need to decide
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So it's false?
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that would be my answer
Next question Find the equation of the quadratic function with zeros 10 and 14 and a vertex at (12, -8).
well f(x) =a(x -10)(x -14) substitute (12, -8) to find a
y = -2x2 − 48x + 280
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