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Complete the proof.Given: AB · BE = CB · BDProve: ΔABC ~ ΔDBE Medals!!!!!!!!!!!!
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please help!!!!!!!!!!!!
|dw:1392240276917:dw|
\(AB · BE = CB · BD \) \(\frac{AB}{BD}=\frac{CB}{BE} \) \(<ABC=<DBE\text { verical angels }\) \(\Delta ABC ~= \Delta DBE\text { ratio +angle so by AAA }\) |dw:1392240730195:dw|
oh thanks your a life saver :)
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