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Mathematics 9 Online
OpenStudy (anonymous):

Complete the proof.Given: AB · BE = CB · BDProve: ΔABC ~ ΔDBE Medals!!!!!!!!!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

please help!!!!!!!!!!!!

OpenStudy (ikram002p):

|dw:1392240276917:dw|

OpenStudy (ikram002p):

\(AB · BE = CB · BD \) \(\frac{AB}{BD}=\frac{CB}{BE} \) \(<ABC=<DBE\text { verical angels }\) \(\Delta ABC ~= \Delta DBE\text { ratio +angle so by AAA }\) |dw:1392240730195:dw|

OpenStudy (anonymous):

oh thanks your a life saver :)

OpenStudy (ikram002p):

np :o

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