Question

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Answer 1

\[\huge\color{blue}{ \frac{-x^2-x+12}{ x^2-8x+15} }\]

Answer 2

\[\huge\color{blue}{ \frac{(x-3)(-x-4)}{ (x-3)(x-5)} }\]

\[\huge\color{blue}{ \frac{\cancel{(x-3) } (-x-4)}{ \cancel{(x-3) }(x-5)} }\]

Answer 3

\[\huge\color{blue}{ \frac{-x-4}{x-5} } \]

Answer 4

What I would do,

\[\huge\color{red}{ \frac{-x-4}{x-5} } \]
\[\huge\color{red}{ \frac{(-1)(x+4)}{(-1)(-x+5)} } \]
\[\huge\color{red}{ \frac{\cancel{ ( - 1 ) } (x+4)}{\cancel{ ( - 1 ) } (-x+5)} } \]
\[\huge\color{red}{ \frac{ x+4}{ -x+5} } \]
\[\huge\color{red}{ \frac{ x+4}{ 5-x} } \]

Answer 5

Thanks a lot for this @SolomonZelman. Very helpful. :)

Answer 6

You welcome!