Question

Use the three steps to solve the problem:
The sum of 3 consecutive integral numbers is 117. Find the numbers.

Answer 1

three steps?

Answer 2

that's what it said

Answer 3

\[x+(x+1)+(x+2)=117\]

Answer 4

\[x+x+1+x+2=117\]

Answer 5

oh okay
i'll try to do it with my own method
let x be one of the numbers
x+1--> second number
x+2--> will be the third one
their sum is 117
so
\(x+ (x+1)+(x+2) =117\)
simplify and solve for x

Answer 6

Lets assume that x is the number, and when you add 1 and 2 to it, you will get the next two consecutive numbers.