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Mathematics 24 Online
OpenStudy (anonymous):

Simplify completely

OpenStudy (anonymous):

OpenStudy (anonymous):

these are the answer choices

OpenStudy (anonymous):

@wolfe8 @AngelCriner @Firejay5 @Mr.ClayLordMath @kadkins15 @xGlisten @Frosty_Flow @hlee13

OpenStudy (anonymous):

I don't fuk with math .. sorry

OpenStudy (anonymous):

(5x^2+9x-2)/(x^2+12x+20) * (x^2+17x+70)/(15x-3)

OpenStudy (anonymous):

So we are left with (5x-1)/(x+10) For the second fraction, we again factor and get [(x+10)(x+7)]/[3∗(5x−1)]

OpenStudy (anonymous):

@hlee13 oh ok

OpenStudy (anonymous):

Multiplying across, our new numerator is (5x-1)(x+10)(x+7) And our new denominator is (x+10)(5x-1)*3 And now we can cancel the (5x-1) and the (x+10) and we are left with (x+7)/3

OpenStudy (anonymous):

does that help at all

OpenStudy (anonymous):

wait a min you kinda lost me

OpenStudy (anonymous):

are you able to show me step by step please i wanna try at least to learn it

OpenStudy (anonymous):

the numerator is the top numbers

OpenStudy (anonymous):

(5x-1)(x+2) * (x+7)(x+10) ---------- ----------- (x+2)(x+10) 3(5x-1) - see if u can simplify this - for example there is (5x-1) on top and bottom so this can be eliminated so it would be x+7/3

OpenStudy (anonymous):

ohh ok ok i kinda understand could you help me with one more please

OpenStudy (anonymous):

i can make it a new question if they would help you

OpenStudy (anonymous):

sure can you make that new question cuz i can't find it

OpenStudy (anonymous):

wait that answer wasnt an answer choice

OpenStudy (anonymous):

??

OpenStudy (anonymous):

wats your answer choices because i have 2 reliable sources saying that is the answer

OpenStudy (anonymous):

besides me

OpenStudy (anonymous):

i had posted the answer choices already

OpenStudy (anonymous):

scroll up

OpenStudy (anonymous):

i said those are the answer choices

OpenStudy (anonymous):

i think its the last one

OpenStudy (anonymous):

are you sure

OpenStudy (anonymous):

idk im just gonna let someone else answer

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

well i will be here waiting for the other person 2 answer

OpenStudy (anonymous):

im sorry i just dont know another way to solve it

OpenStudy (anonymous):

thats ok i will take your word for on this question thanks for at least helping me out with this

OpenStudy (anonymous):

your welcome

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