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8 square root of 2 times square root of 3
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8√2×√3, what are you trying to do with this expression?
it is a special triangle, 30-60-90 the short leg is \[8\sqrt{2} \] and i dont know how to get the other leg :/
|dw:1392249057290:dw|
yes except the angles would be switched
|dw:1392249152378:dw|
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nevermind.
bisecting an equilateral triangle (with sidelenghts 2)|dw:1392249230111:dw| reveals a 30-60-90 triangle
using pythagorus, (a^2+b^2=c^2) [missing side]^2 + 1^2 = 2^2 solving for the missing side [missing side]^2 = 2^2 - 1^2 [missing side] = √(2^2 - 1^2) = √(4-1) = √3
|dw:1392249449119:dw|
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