Question

The sum of a number and its square is 182. Find the numbers.

Answer 1

let the number be \(x\). The square of the number is then \(x^2\). Sum of the number and its square would be \(x+x^2\). The sum of the number and its square equals 182, so
\[x+x^2=182\]

Answer 2

Solve for \(x\), and don't forget to find \(x^2\) as well.