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OpenStudy (anonymous):
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution
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OpenStudy (anonymous):
x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous
OpenStudy (whpalmer4):
\[-4\sqrt{x-3} = 12\]How might you go about solving this?
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