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if log 4 = 0.602 and log 7=0.845 solve log 1/4 and log 49/64
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\(\log(1/4) = -\log(4)\) \(\log(49/64) = \log(49) - \log(64) = \log\left(7^{2}\right) - \log\left(4^{3}\right) \) Can you take it from there?
yes Thank you so much!
You have to look around, particularly when you are given an odd piece of information. Seriously, why would you need log(7)? There has to be a reason.
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