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please help and show steps: x^2 + x -56
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\[x ^{2}+x-56\]
assume this = 0
What two numbers multiply to give you -56 but add to give you 1?
(x+a)(x+b) ab=-56 a+b=1 a=-7 b=8
So, $$ \large x^2+x-56=(x+8)(x-7) $$
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