Question

Solve the system of equations.

2x + 3y = 13
–6x + 4y = 0
A. (2, 3)
B. (1/2, 4)
C. (5, 1)
D. (–2, –3)

Answer 1

you can use a process called substitution

Answer 2

multiply the first part by -3

Answer 3

Multiply the top one by 3:
\[\LARGE 6x+9y=39\]
\[\LARGE -6x+4y=0\]
Now add them:
\[\LARGE 13y=39\]
Divide by 13:
\[\LARGE y=3\]
Plug on y to solve for x: