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OpenStudy (anonymous):
Solve the system of equations. 2x + 3y = 13 –6x + 4y = 0 A. (2, 3) B. (1/2, 4) C. (5, 1) D. (–2, –3)
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OpenStudy (anonymous):
you can use a process called substitution
OpenStudy (anonymous):
multiply the first part by -3
OpenStudy (luigi0210):
Multiply the top one by 3: \[\LARGE 6x+9y=39\] \[\LARGE -6x+4y=0\] Now add them: \[\LARGE 13y=39\] Divide by 13: \[\LARGE y=3\] Plug on y to solve for x:
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