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Find the roots (including the complex numbers) of the quadratic f(x)=x^2-3x+4 . Then find all complex numbers where the f(x) is a real number. Show all work to justify your answer.
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\[x^2-3x+4=0\\ax^2+bx+c=0\\x=\frac{-b \pm \sqrt{b^2-4ac}}{2}\] \[x=\frac{ +3 \pm \sqrt{9-16}} {2}=\frac{ +3 \pm \sqrt{-7}} {2}=\frac{3 \pm \sqrt{7}i }{2}\]
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