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Ca(NO3)2 + Na2SO4 --> CaSO4 + 2NaNO3 Calcium nitrate of 4,92 gr dissolved in water until the volume is 150 ml, then 50 ml of the solution mixed with 0.5 M Na2SO4 completely. Determine how much (gr) of CaSO4 formed and how much (ml) of 0.5 M Na2SO4 that is needed.
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Well, 50 ml of 150 ml is 1/3 of the total amount of Ca(NO3)2. Is that enough hint?
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