Question

help with this

http://prntscr.com/2s4qqq

Answer 1

since this one is a parallelogram
DH = HF ( diagonals bisect each other)
GH = HE ( " " )
so
since
DH = HF
y + 4 = 3x -1 ------(1)

also
we can say
GE = GH + HE
since
GH = HE
GE = 2HE
so...
28 = 2(3x + 2)
3x + 2 = 28/2
3x + 2 = 14
3x = 12
x = 4

if u substitute x = 4 in (1)
y + 4 = 3x - 1
y + 4 = (3*4) -1
y + 4 = 12 - 1
y + 4 = 11
y = 7

got it :) ?

Answer 2

thanks