Question

. In the following equation, identify the x-intercepts in the graph y = 3x2 + 19x – 40

Answer 1

x intercepts mean the value of x when y = o

Answer 2

take
y = 3x2 + 19x – 40
and when y = 0

0 = 3x2 + 19x – 40
now solve this for x...that the answer..

may i help to continue or can u continue this from here ?

Answer 3

can you keep going?

Answer 4

u can use the formula to find the x value ..
when
\[ax^{2} + bx + c = 0\]
\[x = \frac{ -b \pm \sqrt{b^{2} - 4ac} }{ 2a }\]

Answer 5

in the given expression
3x^2 + 19x -40 = 0
a = 3
b = 19
c = (-40)

now plug those values to the formula

Answer 6

\[x = \frac{ -19 \pm \sqrt{19^{2} - 4[3\times(-40) }] }{ 6 }\]

Answer 7

\[x = \frac{ -19 \pm \sqrt{361 + 480} }{ 6}\]