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difference in simplest form? (n^2+3n+2/n^2+6n+8) - (2n/n+4)
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@evanellis8888
@gorv
@gorv
HELP! please
\[\frac{ (n+2)(n+1) }{ (n+4)(n+2) }- \frac{ 2n }{ n+4 }\]
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\[\frac{ n+1 }{ n+4 }-\frac{ 2n }{ n+4 }=\frac{ n+1-2n }{ n+4 }=\frac{ -n+1 }{ n+4 }\]
uhhhh so thats it?
hello?
yeah......sorry for late
today problem with my net
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ok so its -n+1/n+4?
yeah
XD thanks
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