Question

the altitude of a triangle is 2cm shorter than its base. THe area is 17.5cm^2. Find the base of the triangle.

Answer 1

since altitude is 2cm shorter than base

altitude (A) = B - 2

\[Area \ \ of \ \ \triangle = \frac{ 1 }{ 2 } \times Altitude \times base\]

Answer 2

Area = (1/2) AB

but
A = (B - 2)

therefor
Area = (1/2) B(B-2)
17.5 = (1/2)B(B-2)

now solve this for B

can u do it ... or should i keep going ?

Answer 3

I can do it thank you!

Answer 4

u r welcome!