If the varsity cheerleaders replace 8 uniforms and 6 poms, the cost is $378. If they replace 6 uniforms and 9 poms, the cost is $333. What is the cost of each uniform and each pom?

Question

anonymous · Answer

let cost of 1 uniform= $x
cost of 1 pom= $ y
Then 8x+6y=378     ...(1)
6x+9y=333              ...(2)
or 2x+3y=111          ...(3)
8x+12y=444             ...(4)
(4) - (1)  gives   
6y=444-378=66
y=66/6=11
calculate x also.