Question

What is the equation of the plane containing the triangle shown?

2x + 3y + z = 6

3x + 2y + 6z = 6

2x + 6y + 3z = 6

6x + 3y + 2z = 6

Answer 1

hint : intercept form of plane

Answer 2

equation of plane wid intercepts \(a, b,c\) :

\(\large \mathbb{\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1}\)

Answer 3

@saarupp ... first of all try finding the values of X,Y and Z...
and then place them in the equations given above..

Answer 4

I don't understand how to find the "values"

Answer 5

look at the 'corners' of given triangle

Answer 6

can u find the coordinates of them ?