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Physics 13 Online
OpenStudy (anonymous):

How high above the surface of the earth is the acceleration due to gravity equal to 6.50 ms^-2? G= 6.67*10^-11, earth mass=5.97*10^24kg, earth radius=6.38*10^6m. please help test tmrw!

OpenStudy (samgrace):

\[g = GM_{E}/r^{2}\] so 6.50 = GM/r^2 , put in your values.

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