Question

cos^2 x-cos x=0

Answer 1

\[\cos x \left( \cos x-1 \right)=0\]
either \[\cos x=0~or~\cos x=1\]
find the values of x.

Answer 2

\[cosx(cosx-1)=0 \]
\[cosx = 1 \rightarrow x = 2k \pi \]\[\cos x=0 \rightarrow x= k \pi + \pi/2\]