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Geometry 9 Online
OpenStudy (anonymous):

What is the general form of the equation for the given circle?

OpenStudy (anonymous):

OpenStudy (anonymous):

@eliassaab

OpenStudy (anonymous):

x^2+y^2-4x-4y+23=0

OpenStudy (anonymous):

+32

OpenStudy (anonymous):

\[(x - 4)^2 + (y - 4)^2 = 9\\ x^2-8 x+y^2-8 y+32=9\\ x^2-8 x+y^2-8 y+23=0\\ \]

OpenStudy (anonymous):

Your 4's must be 8

OpenStudy (anonymous):

2(4) x= 8x

OpenStudy (anonymous):

x^2 + y^2 − 8x − 8y + 23 = 0 thanks

OpenStudy (anonymous):

Yes

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